User blog comment:Wildoneshelper/Poll on difficulty approach/@comment-19914291-20131106070946

can i suggest another approach (average method)?

allocate no. 1 to 8 from the easiest to insanely hard. then from the poll results add up all the no and find the average, which is then round off to decide the difficulty. eg. if 5 ppl voted easy and 2 voted insanely hard. then the average will be (5X1 + 2X8)divided by 7 = 3. and 3 will correspond to considerably easy.